Find The Sum Of The First 10 Non-Negative Powers Of 2

Similar to before, compute

                                           Suppose,   S = (2^0  + 2^1 + . . . .+ 2^8 + 2^9)
                                                  and,    2S = (2^1 + 2^2 +2^3 + . . . + 2^9 + 2^10)
                                    
                                          From Above We Can Get,  
                                                                                      S = (2S - S)
                                                                                         = (2^10 - 2^0)
                                                                                         = 1024 - 1
                                                                                         = 1023